20.66 (2022)
OpenA Schmidt $(p, q)$-group is a finite non-nilpotent group all of whose proper subgroups are nilpotent and whose Sylow $p$-subgroup is normal. The $N$-critical graph $\Gamma_{Nc}(G)$ of a finite group $G$ is a directed graph on the vertex set of all prime divisors of $|G|$ in which $(p, q)$ is an edge of $\Gamma_{Nc}(G)$ if and only if $G$ has a Schmidt $(p, q)$-subgroup.
Suppose that a finite group $G$ is such that $G = AB = AC = BC$, where $A, B, C$ are subgroups of $G$. Is
$$\Gamma_{Nc}(G) = \Gamma_{Nc}(A) \cup \Gamma_{Nc}(B) \cup \Gamma_{Nc}(C)?$$
This is true if $A, B, C$ are soluble.
Proof claims
Proof claims are the responsibility of the submitter. Appearance here does not mean the claim has been checked for mathematical correctness.
Moderators only screen for spam, abuse, and obviously low-effort submissions.
No proof claims yet.
Log in to claim a proof.
Comments
No comments yet. Be the first to comment.
Log in to post a comment.