19.74 (2018)
OpenA subgroup $H$ of a group $G$ is called pronormal if $H$ and $H^g$ are conjugate in $\langle H, H^g \rangle$ for every $g \in G$. A subgroup $H$ of a group $G$ is called abnormal if $g \in \langle H, H^g \rangle$ for every $g \in G$. Does there exist an infinite group that does not contain nontrivial proper pronormal subgroups?
The question is equivalent to the following: does there exist an infinite simple group that does not contain proper abnormal subgroups?
Progress
*Yes, it does (S. Corson, Monatsh. Math. (2025) https://doi.org/10.1007/s00605-025-02116-8).
Proof claims
Proof claims are the responsibility of the submitter. Appearance here does not mean the claim has been checked for mathematical correctness.
Moderators only screen for spam, abuse, and obviously low-effort submissions.
No proof claims yet.
Log in to claim a proof.
Comments
No comments yet. Be the first to comment.
Log in to post a comment.