19.67 (2018)
SolvedLet $G \leqslant \text{Sym}(\Omega)$, where $\Omega$ is finite. The 2-closure $G^{(2)}$ of the group $G$ is defined to be the largest subgroup of $\text{Sym}(\Omega)$ containing $G$ which has the same orbits as $G$ in the induced action on $\Omega \times \Omega$. Is it true that if $G$ is solvable, then every composition factor of $G^{(2)}$ is either a cyclic or an alternating group?
Progress
No, it is not true (S. V. Skresanov, Algebra Logic, 58, no. 3 (2019), 249–253).
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