19.37 (2018)
Solveda) Does there exist an absolute constant $k$ such that for any nilpotent injector $H$ of an arbitrary finite group $G$ there are $k$ conjugates of $H$ the intersection of which is equal to the Fitting subgroup $F(G)$ of $G$?
b) Can one choose $k = 3$ as such a constant? This is true for finite soluble groups (D. S. Passman, Trans. Amer. Math. Soc., 123, no. 1 (1966), 99–111; A. Mann, Proc. Amer. Math. Soc., 53, no. 1 (1975), 262–264).
Progress
Yes, one can choose $k = 3$ as such a constant, mod CFSG (V. I. Zenkov, Siberian Math. J., 62, no. 4 (2021), 621–637).
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