18.67 (2014)
OpenSuppose that a finite group $G$ admits a Frobenius group of automorphisms $FH$ with kernel $F$ and complement $H$ such that $C_G(F) = 1$. Is the exponent of $G$ bounded in terms of $|F|$ and the exponent of $C_G(H)$?
Progress
This was proved when $F$ is cyclic (E. I. Khukhro, N. Y. Makarenko, P. Shumyatsky, Forum Math., 26 (2014), 73–112) and for $FH \cong A_4$ when $(|G|, 3) = 1$ (P. Shumyatsky, J. Algebra, 331 (2011), 482–489).
Proof claims
Proof claims are the responsibility of the submitter. Appearance here does not mean the claim has been checked for mathematical correctness.
Moderators only screen for spam, abuse, and obviously low-effort submissions.
No proof claims yet.
Log in to claim a proof.
Comments
No comments yet. Be the first to comment.
Log in to post a comment.