18.24 (2014)
OpenFor a group $G$, a function $\phi: G \to \mathbb{R}$ is a quasimorphism if there is a least non-negative number $D(\phi)$ (called the defect) such that $|\phi(gh) - \phi(g) - \phi(h)| \leqslant D(\phi)$ for all $g, h \in G$. A quasimorphism is homogeneous if in addition $\phi(g^n) = n\phi(g)$ for all $g \in G$. Let $\phi$ be a homogeneous quasimorphism of a free group $F$. For any quasimorphism $\psi$ of $F$ (not required to be homogeneous) with $|\phi - \psi| < $ const, we must have $D(\psi) \geqslant D(\phi)/2$. Is it true that there is some $\psi$ with $D(\psi) = D(\phi)/2$?
Proof claims
Proof claims are the responsibility of the submitter. Appearance here does not mean the claim has been checked for mathematical correctness.
Moderators only screen for spam, abuse, and obviously low-effort submissions.
No proof claims yet.
Log in to claim a proof.
Comments
No comments yet. Be the first to comment.
Log in to post a comment.