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17.37 (2010)

Open

Is there an integer $n$ such that for all $m > n$ the alternating group $A_m$ has no non-trivial $A_m$-permutable subgroups? (See the definition in 17.112.)

Contributor: A. F. Vasil’ev, A. N. Skiba

Progress

*Yes, there is (N. Yang, A. Galt, Bull. Malays. Math. Sci. Soc. (2), 46, no. 5 (2023), Paper no. 177, 16 p.).

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