15.86 (2002)

Solved

A group $G$ is called discriminating if for any finite set of nontrivial elements of the direct square $G \times G$ there is a homomorphism $G \times G \to G$ which does not annihilate any of them (G. Baumslag, A. G. Myasnikov, V. N. Remeslennikov). A group $G$ is called squarelike if $G$ is universally equivalent (in the sense of first order logic) to a discriminating group (B. Fine, A. M. Gaglione, A. G. Myasnikov, D. Spellman). Must every squarelike group be elementarily equivalent to a discriminating group?

Progress

Yes, it must (O. Belegradek, J. Group Theory, 7, no. 4 (2004), 521–532; B. Fine, A. M. Gaglione, D. Spellman, Archiv Math., 83, no. 2 (2004), 106–112).

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