21.27 (2026)
Open(M. Larsen, A. Shalev, P. H. Tiep). A permutation on a set $\Omega$ is called a derangement if it has no fixed points in $\Omega$. Let $G$ be a finite simple transitive permutation group. Is it true that every element in $G$ is the product of two derangements?
Proof claims
Proof claims are the responsibility of the submitter. Appearance here does not mean the claim has been checked for mathematical correctness.
Moderators only screen for spam, abuse, and obviously low-effort submissions.
No proof claims yet.
Log in to claim a proof.
Comments
No comments yet. Be the first to comment.
Log in to post a comment.