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16.57 (2006)

Solved

Suppose that $\omega(G) = \omega(L_2(7)) = \{1, 2, 3, 4, 7\}$ (see 16.57 for notation). Is $G \cong L_2(7)$? This is true for finite $G$.

Contributor: V. D. Mazurov

Progress

Yes, it is (D. V. Lytkina, A. A. Kuznetsov, Siberian Electr. Math. Rep., 4 (2007), 136–140; http://semr.math.nsc.ru).

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