14.13 (1999)

Solved

a) By definition the commutator length of an element $z$ of the derived subgroup of a group $G$ is the least possible number of commutators from $G$ whose product is equal to $z$. Does there exist a simple group on which the commutator length is not bounded?
b) Does there exist a finitely presented simple group on which the commutator length is not bounded?

Progress

a) Simple groups with this property were constructed in (J. Barge, É. Ghys, Math. Ann., 294 (1992), 235–265), and finitely generated simple ones in (A. Muranov, Int. J. Algebra Comput., 17 (2007), 607–659).
b) Yes, there does (P.-E. Caprace, K. Fujiwara, Geom. Funct. Anal., 19 (2010), 1296–1319).

Comments

All comments are the responsibility of the user. Comments appearing on this page are not verified for correctness. Please keep posts mathematical and on topic. If you want to submit a proof (or a partial proof), please use the dedicated proof submission form rather than posting it in the comments.
Order by newest first or oldest first.

No comments yet. Be the first to comment.

Proof claims

Proof claims are the responsibility of the submitter. Appearance here does not mean the claim has been checked for mathematical correctness. Moderators only screen for spam, abuse, and obviously low-effort submissions.

No proof claims yet.