13.39 (1995)
Partially SolvedLet $A$ be an associative ring with unity and with torsion-free additive group, and let $F^A$ be the tensor product of a free group $F$ by $A$ (A. G. Myasnikov, V. N. Remeslennikov, Siberian Math. J., 35, no. 5 (1994), 986–996); then $F^A$ is a free exponential group over $A$; in (A. G. Myasnikov, V. N. Remeslennikov, Int. J. Algebra Comput., 6 (1996), 687–711), it is shown how to construct $F^A$ in terms of free products with amalgamation.
$\qquad$ a) (G. Baumslag). Is $F^A$ residually nilpotent torsion-free?
$\qquad$ b) Is $F^A$ a linear group?
$\qquad$ c) (G. Baumslag). Is the Magnus homework of $F^\mathbb{Q}$ into the group of power series over the rational number field $\mathbb{Q}$ faithful or not?
$\qquad$ d) Is the universal theory of $F^A$ decidable?
$\qquad$ e) (G. Baumslag). Can free $A$-groups be characterized by a length function?
$\qquad$ f) (G. Baumslag). Does a free $\mathbb{Q}$-group admit a free action on some $\Lambda$-tree? See definition in (R. Alperin, H. Bass, in: Combinatorial group theory and topology, Alta, Utah, 1984 (Ann. Math. Stud., 111), Princeton Univ. Press, 1987, 265–378).
Progress
a) Yes, it is (A. Jaikin-Zapirain, Ann. Sci. Éc. Norm. Supér. (4), 57, no. 4 (2024), 1101–1133).
b) In the case where $\langle 1 \rangle$ is a pure subgroup of the additive group of $A$, there is an affirmative answer to b) (A. M. Gaglione, A. G. Myasnikov, V. N. Remeslennikov, D. Spellman, Commun. Algebra, 25 (1997), 631–648). It is also known that the Magnus homomorphism is one-to-one on any subgroup of $F^{\mathbb{Q}}$ of the type $\langle F, t \mid u = t^n \rangle$ (G. Baumslag, Commun. Pure Apply. Math., 21 (1968), 491–506).
c) Yes, it is faithful (A. Jaikin-Zapirain, Ann. Sci. Éc. Norm. Supér. (4), 57, no. 4 (2024), 1101–1133).
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