11.52 (1990)

Solved

(Well-known problem). A permutation group on a set $\Omega$ is called sharply doubly transitive if for any two pairs $(\alpha, \beta)$ and $(\gamma, \delta)$ of elements of $\Omega$ such that $\alpha \neq \beta$ and $\gamma \neq \delta$, there is exactly one element of the group taking $\alpha$ to $\gamma$ and $\beta$ to $\delta$. Does every sharply doubly transitive group possess a non-trivial abelian normal subgroup?

Progress

A positive answer is well known for finite groups. But for the general case, the answer is no, not every (E. Rips, Y. Segev, K. Tent, J. Europ. Math. Soc., 19, no. 10 (2017), 2895–2910).

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